Agreed!

explain why the following limit does not exist: lim x-->0 cotxsecx

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Answer:

Consider the limit and change each trig function into terms of `sinx` and `cosx` .

`lim_{x->0}cotx secx`

`=lim_{x->0}{cosx}/{sinx} cdot 1/{cos x}`   cancel common factors

`=lim_{x->0}1/{sin x}`   

As `x->0` , `sinx->0` which means that the limit can't exist since the limit approaches `1/0` which does not exist.

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