Agreed!

How to solve a problem in chemistry?

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Answer:
Solution: n2*3 27G*98g 3*22.4 l n2Al + 3H2SO4 = 3H2 + Al2(SO4)3 PU x 6,72 l Matsuda: n3*98g/x = 3*22.4 l/6,72 L. x = 3*98g*of 6.72 l/3*22.4 l = 29,4 g of sulfuric acid. n2*27G/y = 3*22.4 l/6,72 L. y = 2*27G*of 6.72 l/3*22.4 l = 5.4 g aluminum. petvet: 29,4 g of sulfuric acid and 5.4 g of aluminium.
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