Agreed!

multiple derivatives determine first,second derivative of y= e^6x-(lnx)/x

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Answer:

We have the expression  y = e^6x - (ln x)/x

The first derivative is 6*e^6x - [x^-1/x - ln x/x^2]

=> 6*e^6x - 1/x^2 + (ln x)/x^2

=> 6*e^6x + (ln x - 1)/x^2

The second derivative is:

36*e^6x + (1/x)/x^2 - 2*(ln x - 1)/x^3

=> 36*e^6x + 1/x^3 - 2*(ln x - 1)/x^3

=> 36*e^6x + (3 - 2*ln x)/x^3

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